4 years ago the age of the father is fourth times the age of son,and after 5 years the sum of their ages will be 73,then what are their present ages?

Tuesday 25th October 2016
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Let the present age of the father and son be x and y respectively.Then,

4 years ago their ages will be x-4 and y-4 respectively.

According to question, 

x-4=4(y-4)

x-4=4y-16

4y-x=12---------------(1)

And their ages after 5 years will be x+5 and y+5 respectively.

Similary,according to question,

x+5+y+5=73

y+x=63-----------------(2)

On adding (1) and (2) we get,

4y-x+y+x=12+63

5y=75

y=15

And,we get from(2)  

15+x=63

x=48

Hence their present ages are 48 and 15 respectively.

 

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