4 years ago the age of the father is fourth times the age of son,and after 5 years the sum of their ages will be 73,then what are their present ages?
Tuesday 25th October 2016
Let the present age of the father and son be x and y respectively.Then,
4 years ago their ages will be x-4 and y-4 respectively.
According to question,
x-4=4(y-4)
x-4=4y-16
4y-x=12---------------(1)
And their ages after 5 years will be x+5 and y+5 respectively.
Similary,according to question,
x+5+y+5=73
y+x=63-----------------(2)
On adding (1) and (2) we get,
4y-x+y+x=12+63
5y=75
y=15
And,we get from(2)
15+x=63
x=48
Hence their present ages are 48 and 15 respectively.
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